Homework Help: Algebra 2

Posted by Mary on Sunday, July 6, 2008 at 3:31pm.

saturn is approximately 1.4 x10^9 kilometers from the Sun. If light travels at approximately 3.0 x 10^5 kilometers per second, how long does it take light from the Sun to reach Saturn? Express your answer in scientific notation.

Algebra 2 - drwls, Sunday, July 6, 2008 at 4:51pm
Divide the separation distance by the speed of light, using scientific notation.

We will be glad to critique your work, if necessary.
Algebra 2 - bobpursley, Sunday, July 6, 2008 at 4:58pm
We will be happy to check your work or thinking.

time=distance/speed
Algebra 2 - Mary, Sunday, July 6, 2008 at 5:36pm
I divided 1.4 x 10^9/3.0 x10^5=
4.7 x 10^4 sec
Algebra 2 - drwls, Sunday, July 6, 2008 at 6:00pm
Try again. You got the exponent wrong
Algebra 2 - Mary, Sunday, July 6, 2008 at 6:36pm
answer=4.7 x10^3
Algebra 2 - Mary, Sunday, July 6, 2008 at 6:43pm
I thought you take 10^9-5 or 10^4 is the exponent
Algebra 2 - drwls, Sunday, July 6, 2008 at 8:33pm
0.47*10^4 = 4.7*10^3
Algebra 2 - Mary, Monday, July 7, 2008 at 7:57am
I understand now. When i divided it gave me .047. Thank you for your help.

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