algebra
posted by jean on .
do I do this correct and if not can you please show and tell me what I did wrong? thank you
6x^27x=3
We have to move the 3 to the left so it becomes
6x^27x3=0
6x^27x3=0 this makes this a quadratic equations 6*x^27*x3=0 and has the answer of 1.5,0 so
0=0
solution is x=1.5, x= 0.3333333333

I don't get the 0=0 step but your solution is correct for x = 1.5 and x = 0.3333.

so can you please show me what i am doing wrong with this?

I don't know that you did anything wrong. How did you solve the quadratic? Did you use the quadratic formula?