Posted by **jean** on Friday, July 4, 2008 at 10:44pm.

using L as the length and W is wide asume L is great then W . If a architect is makiing a swimming pool to go into a rectangular area of fencing and she uses 6 yards of fencing to enclose a rectangular area of 352 square yards what would the dinension be for L and W?

- Math- algebra -
**drwls**, Saturday, July 5, 2008 at 5:13am
Is your 6 yards of fencing a misprint? That is not enough to enclose the required area.

- Math- algebra -
**drwls**, Sunday, July 6, 2008 at 7:44am
Then L*W = 352 and

2(L + W) = 60

Solve the two simultaneous equations. Let L = 352/W

2(352/W +W) = 60

(352/W) + W = 30

W^2 - 30W + 352 = 0

There is no real solution. 60 yards of fencing is not enough to enclose 352 sq. yards. You need at least 75 yards

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