Sunday

December 21, 2014

December 21, 2014

Posted by **jean** on Thursday, July 3, 2008 at 8:55am.

Prove (algebraically, not numerically) that the product of the solutions of

ax^2+bx+c=0 is c/a

- second post algebra -
**Reiny**, Thursday, July 3, 2008 at 9:19amRemember that the quadratic formula gives you the solution

x = (-b ±√(b^2-4ac))/(2a)

so when we multiply these two solutions we get

(-b+√(b^2-4ac))/(2a) * (-b-√(b^2-4ac))/(2a)

= (b^2 - (b^2-4ac))/(4a^2)

= 4ac/(4a^2)

= c/a

**Answer this Question**

**Related Questions**

algerba - does anyone have a clue how to do this. I am so lost. If you can ...

algebra - Give the equation of the line that passes through point (5, 1) and is ...

english - can someone please help me with my previous post...i don't have a clue...

2nd grade math requestion post - Okay, my child is doing problem solving lesson ...

College Algebra - 1. 2log8^x=log8(4x+12) both log bases are 8. I have no clue ...

Statistics - Given the following information, determine the 68.3 percent, 95.5 ...

Java - Can anybody help me figure how to post a Java file to as an attachment. I...

to Hussam - Please click on Post a New Question when you need to post a question...

algebra 1 - please help I have no clue how to do this b-9+6b =30

history - please could someone help i have got a crossword about the Treaty of ...