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second post algebra

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does anyone have a clue how to do this. I am so lost. If you can please explan why you do what you do when working this out so maybe i can better understand this. thanks a bunch.
Prove (algebraically, not numerically) that the product of the solutions of
ax^2+bx+c=0 is c/a

  • second post algebra -

    Remember that the quadratic formula gives you the solution
    x = (-b ±√(b^2-4ac))/(2a)

    so when we multiply these two solutions we get
    (-b+√(b^2-4ac))/(2a) * (-b-√(b^2-4ac))/(2a)
    = (b^2 - (b^2-4ac))/(4a^2)
    = 4ac/(4a^2)
    = c/a

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