Thursday

July 31, 2014

July 31, 2014

Posted by **jean** on Thursday, July 3, 2008 at 8:55am.

Prove (algebraically, not numerically) that the product of the solutions of

ax^2+bx+c=0 is c/a

- second post algebra -
**Reiny**, Thursday, July 3, 2008 at 9:19amRemember that the quadratic formula gives you the solution

x = (-b ±√(b^2-4ac))/(2a)

so when we multiply these two solutions we get

(-b+√(b^2-4ac))/(2a) * (-b-√(b^2-4ac))/(2a)

= (b^2 - (b^2-4ac))/(4a^2)

= 4ac/(4a^2)

= c/a

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