posted by here on .
The first step of the synthesis is described by the reaction below. When 2.000 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4, the theoretical yield of FeC2O42H2O is
Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)
Did you omit the arrow? I assume the first line holds the reactants and the second line holds the products.
Convert 2.000 g of the iron ammonium sulfate hexahydrate to mols. Convert 13 mL of the 1 M oxalic acid to mols. Determine the mols of the product formed FROM EACH of the reactants, TAKE THE SMALLER ONE and that will be the limiting reagent. Usual stoichiometry after that. Post your work if you need further assistance.
the answer is .918