SIMPLIFY BY REMOVING FACTORS OF 1.

q^2-64/(q+8)^2

q^4+16q^3+64q^2-64/(q+8)^2

is this answer correct, can you help me .

I don't know how you got your answer, nor what you mean by "removing factors of 1" but

(q^2-64)/(q+8)^2
=(q+8)(q-8)/(q+8)^2
=(q-8)/(q+8) , q not equal to -8

thanks

To simplify the expression (q^2-64)/(q+8)^2, we can first factor the numerator as a difference of squares. Recall that a difference of squares can be factored as (a^2 - b^2) = (a + b)(a - b).

Now let's apply this to the numerator:
q^2 - 64 = (q + 8)(q - 8)

So, the expression becomes:
((q + 8)(q - 8))/(q + 8)^2

Next, we can cancel out common factors in the numerator and denominator. In this case, we have (q + 8) as a common factor.

Cancelling out (q + 8) from the numerator and denominator, we are left with:
(q - 8)/(q + 8)

Therefore, the simplified form of the expression (q^2-64)/(q+8)^2 is (q - 8)/(q + 8).

Regarding your second expression, (q^4 + 16q^3 + 64q^2 - 64)/(q + 8)^2, it is not the simplification of the original expression (q^2-64)/(q+8)^2. These expressions are different.

If you have any further questions or doubts, feel free to ask.