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October 1, 2014

October 1, 2014

Posted by **Cynthia** on Wednesday, July 2, 2008 at 8:21am.

q^2-64/(q+8)^2

q^4+16q^3+64q^2-64/(q+8)^2

is this answer correct, can you help me .

- Algebra -
**Reiny**, Wednesday, July 2, 2008 at 8:35amI don't know how you got your answer, nor what you mean by "removing factors of 1" but

(q^2-64)/(q+8)^2

=(q+8)(q-8)/(q+8)^2

=(q-8)/(q+8) , q not equal to -8

- Algebra -
**Cynthia**, Wednesday, July 2, 2008 at 8:49amthanks

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