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I am too embarassed to ask this Calculus (really pre-calculus) question in tutoring, because I know I should know. Is the inverse of f(x)=3x-1 actually f(x)=1/3x+1? How do I find it? What if it asks the same equation replaced with f to the -1 power (x)? I think I know how the F of -1 power (x) is x+1/3, but I know that from watching someone else.

  • Pre-Calculus/Calculus -

    Ok. An inverse function is formed from switch in the input and output variables(x,y).

    so y = 3x -1
    flip x = 3y-1 and solve for y again
    y = 1/3(x+1)
    so f^-1(x) = 1/3(x+1)
    and the inverse of an inverse function is the original equation: f(x) = 3x-1

  • Pre-Calculus/Calculus -

    okay, thanks!

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