Monday
April 27, 2015

Homework Help: chemistry

Posted by Anonymous on Tuesday, July 1, 2008 at 9:11pm.

I'm asked to write the molecular, ionic, and net ionic equation. Then, I'm supposed to provide an explaination of conductivities observed. Below I have written only the net ionic equation and a brief explanation I think of the first two conductivities observed. However, I did not have any clue on how to explain that last two. Can you check and help me with the explanations? Thanks for the help!

why would the mixture between 0.1 M acetic acid (conductivity of 7) and 0.1 M ammonia (conductivity of 8) result in a conductivity of 8?

Net ionic equation: HC2H3O2 (aq) + NH3 (aq) -> NH4+ (aq) + C2H3O2^- (aq)

Explanation: We see an increase (7 to 8) in conductivity because the products are completely ions like NH4^+ (aq) and C2H3O2^- (aq) in the net ionic equation.

why would the mixture between 0.1 M sulfuric acid (conductivity of 9) and 0.1 M barium hydroxide (conductivity of 7) result in a conductivity of 7?

Net ionic equation: 2H^+ (aq) + SO4^-2 (aq) + Ba^+2 (aq) + OH^-(aq) -> 2H2O (l) + BaSO4 (s)

Explanation: We see a decrease (9 to 7) in conductivity due to the fewer ions started with in reactant compared to the products, which consist of a solid and molecule.

why would the mixture between 0.1 M copper (II) sulfate (conductivity of 9) and 0.1 M hydrosulfuric acid (weak conductivity of electricity) result in a conductivity of 9?

Net ionic equation: Cu^+2 (aq) + H2S(g) -> CuS(s) + H^+ (aq)

We see the conductivity remain the same as the copper (II) sulfate.

why would the mixture between 0.1 M copper (II) acetate (conductivity of 9) and 0.1 M hydrosulfuric acid (weak conductivity of electricity) result in a conductivity of 9?

Net ionic equation: Cu^+2 (aq) + 2C2H3O2^- (aq) + H2S (aq) -> CuS (s) + 2HC2H3O2 (aq)

We see the conductivity remain the same as the copper (II) acetate.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Members