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December 21, 2014

December 21, 2014

Posted by **C** on Tuesday, July 1, 2008 at 4:34pm.

Add (simplify if possible)

(x^2 + 11x)/(x^2 - 3x) + (x^2 - 6x)/(x^2 - 3x)

I actully came up with two possible answers.

(2x+5)/x-3 and (2x^2-5)/x-6x

I'm not sure which answer is correct.

- algebra -
**drwls**, Tuesday, July 1, 2008 at 6:29pmThe denominators of the two added terms can be written x(x-3). The x^2-6x term can be written x(x-6). Therefore

(x^2 + 11x)/(x^2 - 3x) + (x^2 - 6x)/(x^2 - 3x) = [x(x+11) + x(x-6)]/[(x(x-3)]

Cancel out the x terms and you get

(2x-5)/(x-3)

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