In each of the following groups, identify the two substances whose aqueous solutions have common properties to a marked degree by circling the two formulas. Explain why you made your choice.
I'm not the two formulas I circle is correct. Below are my explanations. Fix me where I am wrong. I appreciate your help!
a) CuS, CuCl2, Na2S, KCl
I know CuS, copper (II) sulfide is insoluble, but CuCl2,copper (II) chloride, Na2S, Sodium Sulfide, and KCl, Potassium Chloride, are soluble. The two out of the three (in which I will circle) I see common characteristics are CuCl2 and KCl, since they both have cations of Cl^-.
b) HCl, HC2H3O2, NaC2H3O2
I'd circle HCl, hydrochloric acid, and NaC2H3O2, Sodium Acetate, because they are strong electrolytes.
I don't see anything wrong with your answers; however, I think it is a poor question. For example, in question (a), why not include Na2S since that is soluble along with CuCl2 and KCl. All three are quite soluble so I would say that was to a marked degree. KCl and CuCl2 DO have the Cl^- as common ions.
For question (b), you are correct that HCl and NaC2H3O2 are strong electrolytes ( but only in solution), but why not include NaC2H3O2 and HC2H3O2 because both contain the acetate ion (although not to a marked degree (and to what extent is a "marked degree"?) since acetic acid is only slightly ionized). HCl with no (aq) after it or something to indicate it is solution, is a gas and is not ionized. Or could HCl and HC2H3O2 both contain hydrogen atoms. I just don't think these are good questions at all.
I hope I've not confused you.
opps I forgot to add NH4C2H3O2 to the list of substances for part (b)
a) CuCl2 and KCl - both soluble and have chlorine ion as anion.
b) NH4C2H3O2 and NaC2H3O2 - both soluble and have acetate ion as anion
SO3 can be produced in the following two-step process:
FeS2 + O2 ---> Fe2O3 + SO2
S02 + O2 ----> SO3
Assuming that all the FeS2 reacts, how many grams of SO3 are produced when 20.0 g of the FeS2 reacts with 16.0 g of O2?
Katrina-
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Your explanations for both parts are correct, but there seems to be a small error in your choice for part a).
a) CuS is indeed insoluble, and CuCl2, Na2S, and KCl are all soluble. However, when looking for substances with common properties, we should look for similarities in their ions or anions.
In this case, CuCl2 has copper (II) cations (Cu^2+) and chloride anions (Cl^-), while KCl has potassium cations (K^+) and chloride anions (Cl^-). The common property here is the chloride anion (Cl^-).
Na2S, on the other hand, has sodium cations (Na^+) and sulfide anions (S^2-), which is different from CuCl2 and KCl.
So, the correct choice would be CuCl2 and KCl, since they both have the chloride anion (Cl^-).
For part b), your explanation is correct. Both HCl (hydrochloric acid) and NaC2H3O2 (sodium acetate) are strong electrolytes, meaning they dissociate completely into ions in aqueous solutions. Therefore, HCl and NaC2H3O2 would be the correct choices for having common properties.