Posted by Kelly on Saturday, June 28, 2008 at 9:36pm.
#1. Have you tried plugging x=3 and y=2 into the equation? Do it and verify that the equation is satisfied there.
Then get the circle's slope dy/dx at (3,2) by implicit differentiation.
Once you know one point on the line (3,2), and the slope at that point, the equation of the line can easily be written.
(y-2) = (x-3)*dy/dx
#2 Rewrite the circle equation
(x-2)^2 -4 + (y-3)^2 -9 + 9 = 0
(x-2)^2 + (y-3)^2 = 4
That tells you the circle's center location and radius. Plot it and the point (5,7) on a graph. Draw a line from (5,7) to the circle's center at (2,3). From the length of that line (a hypotenuse) and the radius of the circle, use the Pythagorean theorem to get the length of the tangent. A tangents, radius to the tangency point, and hypotenuse form a right triangle.
3. That's all I have time for. Please show your own work on future posts
Related Questions
mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....
mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....
mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....
mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....
calculus - Conic sections A circle passes through points A(-5,2), B(-3,-4) and C...
Calculus - Conic Sections- A point moves so that its distance from the origin is...
calculus - if the tangent of two intersecting circles, at their points of ...
Math (Pre Cal) - Hi, I am studying for a precalculus quiz and I do not ...
math - can u help this the qustion is : A circle passes through the points (1,4...
steev - can u help this the qustion is : A circle passes through the points (1,4...
For Further Reading
