Three consecutive integers are such that when they are taken in increasing order and
multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
I want how you do that not the answer only
Answer is 7,8,9
Let the first integer be X, the second X+1 and the third X+2.
2X + 3(X+1) + 4(X+2) = 74
I hope this helps. Thanks for asking.