Write balanced equations showing how HBr and SO2 are consumed in a gas trap containing NaOH.

Here are the two partial chemical equations with one formula for you to fill in in each one:

Please note:
*SO2 in a water solution is equivalent to sulfurous acid, H2SO3
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NaOH + HBr ---> NaBr + ______

2NaOH + SO2 ---> Na2SO3 + ______

thanks!

H2O

To write balanced equations showing how HBr and SO2 are consumed in a gas trap containing NaOH, we need to understand the reaction between these compounds.

When HBr (hydrobromic acid) and NaOH (sodium hydroxide) react, they undergo a neutralization reaction. The hydrogen ion (H+) from HBr combines with the hydroxide ion (OH-) from NaOH to form water (H2O), while the sodium (Na+) from NaOH combines with the bromide ion (Br-) from HBr to form sodium bromide (NaBr). The balanced equation for this reaction is:

HBr + NaOH → NaBr + H2O

Now, let's consider the reaction between SO2 (sulfur dioxide) and NaOH. When these two compounds react, they undergo an acid-base reaction. The sulfur dioxide reacts with the hydroxide ion to form sodium sulfite (Na2SO3) and water. The balanced equation for this reaction is:

SO2 + 2 NaOH → Na2SO3 + H2O

So, the balanced equations showing how HBr and SO2 are consumed in a gas trap containing NaOH are:

1) For HBr:
HBr + NaOH → NaBr + H2O

2) For SO2:
SO2 + 2 NaOH → Na2SO3 + H2O

These equations illustrate the chemical reactions that occur between HBr, SO2, and NaOH when they are introduced into a gas trap.