Intelligence quotients on the Stanford-Binet intelligence test are normally distributed with a mean of 100 and a standard deviation of 16. Use the 68-95-99.7 rule to find the percentage of people with the following IQs:
a.) between 84 and 100
b.) below 52
a) One standard deviation is 16, that is a score of 84. 68 percent will have a score of 100+-16, so 34 percent will have a score from 84 to 100.
b. How many standard deviations is a score of 52?
thank you
The standard devation is the same for b.) as it is for a.)
Yes, of course it is. So how many standard deviations is it to a score of 52?
oh ok so 2.
I meant 3
so would it be
100-16(3) =52
100-99.7=.03