1A student measures the velocity of the water in a stream as 2.5 meters per second. The actual velocity of the water is 3.0 meters per second. What is the approximate percent deviation of the student’s measurements?
(1)0.50%
(2)17%
(3)20%
(4)50%
Is it (2)?
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To find the approximate percent deviation, you need to calculate the difference between the student's measurement and the actual value, and then divide it by the actual value. After that, multiply the result by 100 to get the percentage.
In this case, the student measured a velocity of 2.5 meters per second, while the actual velocity was 3.0 meters per second.
The difference between the two values is 3.0 - 2.5 = 0.5
To find the percent deviation, divide the difference (0.5) by the actual value (3.0):
0.5 ÷ 3.0 = 0.1667
Multiplying this by 100, we get:
0.1667 × 100 ≈ 16.67%
So, the approximate percent deviation is approximately 16.67%.
Therefore, the correct answer is (2) 17%, as it is the closest option to our calculated result.