CAN YOU LET ME KNOW IF I DID THIS PROBLEM .SOLVE
x²+8x+12=0
I can definitely say you did not do this problem. I don't see an answer posted.
x^2+8x+12=0
split middle term
as
X^2+6X+2X=12=0
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taking out common factor
X(X+6) + 2(X+6)
(x+6) (x+2)=0
X=-6;-2
Of course! I can help you solve the quadratic equation x² + 8x + 12 = 0.
To solve this quadratic equation, you can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In the given equation, a = 1, b = 8, and c = 12.
Now, let's substitute these values into the quadratic formula:
x = (-(8) ± √((8)² - 4(1)(12))) / (2(1))
Simplifying further:
x = (-8 ± √(64 - 48)) / (2)
x = (-8 ± √16) / 2
x = (-8 ± 4) / 2
Now, we will solve for two possible values of x.
First, with the positive square root:
x₁ = (-8 + 4) / 2
x₁ = -4 / 2
x₁ = -2
Next, with the negative square root:
x₂ = (-8 - 4) / 2
x₂ = -12 / 2
x₂ = -6
So, the two solutions to the equation x² + 8x + 12 = 0 are x₁ = -2 and x₂ = -6.