Posted by jean on Wednesday, June 18, 2008 at 9:18am.
Can anyone help me understand how to do this?
Factoring each polynomial
x^2+5ax+6a^2
and
solve each equation
a^2+a=20
I am so lost with this one I can not grab how you get a number from this.
thanks for trying who ever you may be

algebra  indu, Wednesday, June 18, 2008 at 9:30am
X^2+5aX+6a^2
splitting the middle term as
X^2+3ax+2aX+6ax^2
 
take common factor from 2 terms,sequentially as
X(X+3a)+2a(X+3a)
(X+2a) (X+3a) answer is x=2a ;X=3a
Question 2: a^2+a20=0
a^2+5a4a20=0
a(a+5)4(a+5)
(a+5) (a4)=0
or a=5 ; +4
both are factorised using splitting the middle term method
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