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December 21, 2014

December 21, 2014

Posted by **jean** on Wednesday, June 18, 2008 at 9:18am.

Factoring each polynomial

x^2+5ax+6a^2

and

solve each equation

a^2+a=20

I am so lost with this one I can not grab how you get a number from this.

thanks for trying who ever you may be

- algebra -
**indu**, Wednesday, June 18, 2008 at 9:30amX^2+5aX+6a^2

splitting the middle term as

X^2+3ax+2aX+6ax^2

------ ---------

take common factor from 2 terms,sequentially as

X(X+3a)+2a(X+3a)

(X+2a) (X+3a) answer is x=-2a ;X=-3a

Question 2: a^2+a-20=0

a^2+5a-4a-20=0

a(a+5)-4(a+5)

(a+5) (a-4)=0

or a=-5 ; +4

both are factorised using splitting the middle term method

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