Posted by Sammie on Tuesday, June 17, 2008 at 9:53pm.
1. Is C=7 supposed to mean Circumference = 7?
If so, C = 2pi(r)
7 = 2pi(r)
r = 7/2pi
= appr. 1.114
2. In the 30-60-90 right-angled triangle, the sides are in the ration 1 : √3 : 2 for the sides across from the corresponding angles.
So If you are given any of the sides, you can set up a ratio.
e.g. suppose the side across from the 60º angle is 12 cm, then
for the hypotenuse h,
h/x = 12/√3
h = 24/√3
3. According to the formula for AB, which you should definitely know for the test,
AB = √[(-5+7)^2 + (1+4)^2]
Midpoint ?? One of the most basic of the fundamental geometry formulas
midpoint = ((-3+1)/2 , (-7-5)/2)
4. Let the altitude be h
then h^2 + 8^2 + 12^2 = (4√15)^2
solve for h
5. I can visualize a cylinder with a height of 8 (the difference in the y-values), and a radius of √(12^2 + (-5)^2)
so volume = pi(r^2)h
= appr. 4247.4 units^3
I just notice a typo in #3
h/x = 12/√3 should say h/2 = 12/√3
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