sovle for x:

4log33x=28. how do i do this....please help:(

33^log33(x) = x = 33^7

= 4.26 * 10^10

To solve the equation 4log33x = 28 for x, you need to apply logarithmic properties and solve for x. Here's how you can do it step by step:

Step 1: Start with the equation 4log33x = 28.

Step 2: Divide both sides of the equation by 4 to isolate the logarithmic expression:
log33x = 7.

Step 3: Use the logarithmic property to rewrite the equation in exponential form. Recall that log33x = y can be rewritten as 3^y = x.
In this case, we have 3^7 = x.

Step 4: Evaluate 3^7 by raising 3 to the power of 7:
3^7 = 2187.

Therefore, the solution to the equation 4log33x = 28 is x = 2187.

Keep in mind that logarithms can have multiple solutions, so it's important to check your answer by plugging it back into the original equation to ensure that it satisfies the equation.