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October 1, 2014

October 1, 2014

Posted by **MILEY!:)7** on Monday, June 16, 2008 at 8:19pm.

f(x)=x^3-x^2+4x-4

I have (x^2+4)(x+1)

so one zero is 1. how do i find the two other zeros.

- alg 2 -
**Damon**, Monday, June 16, 2008 at 8:22pmif +1 is a zero, (x-1) is a factor because (x-1) is zero when x = 1

- alg 2 -
**Damon**, Monday, June 16, 2008 at 8:27pmI have

(x^2+4)(x-1)

then when is (x^2 + 0 x +4 )= 0??

x = [ 0 +/- sqrt (0 -16) ] / 2

x = +/- 2 i (imaginary roots)

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