Write Y= 9/4x+3/2 in standard form..
the answer I got was -9/4+y=3/2
I don't understand why I got it wrong
Ax + By = C
is standard form
here you have
(9/4) x - y = -3/2
multiply both sides by 4 to get rid of fractions
9 x - 4 y = -6
You have lost the x variable
from your equation Y= 9/4x+3/2
multiply each term by 4, the LCD
4y = 9x + 6
0 = 9x - 4y + 6 (1)
or 9x - 4y = -6 (2)
Most texts call version (1) general form
and version (2) standard form
To write the equation Y = 9/4x + 3/2 in standard form, you need to rearrange the equation so that the x and y terms are on the same side of the equation, and the coefficients of x and y are integers.
To do this, let's start by getting rid of the fraction coefficients. Multiply the entire equation by the common denominator of 4 to eliminate the fractions:
4 * Y = 4 * (9/4x + 3/2)
4Y = 9x + 6
Next, move the y term to the other side of the equation by subtracting 4Y from both sides:
-4Y + 4Y = 9x - 4Y + 6
0 = 9x - 4Y + 6
Now, let's further rearrange the equation to have the variables in alphabetical order:
9x - 4Y + 6 = 0
Therefore, the standard form of the equation Y = 9/4x + 3/2 is 9x - 4Y + 6 = 0. Your answer: -9/4 + Y = 3/2 is incorrect because it doesn't follow the convention of standard form.