Please help me check my answer.
Solve by completing the square.
x^2-4x=10
x^2-4x=10
x^2 - 4x + 4 = 10 + 4
(x-2)^2 = 14
x-2 = ±√14
x = 2 ±√14
Thanks Reiny I was on the right track I had miss one step I had half of the answer.
To solve the quadratic equation by completing the square, follow these steps:
Step 1: Move the constant term to the other side of the equation.
x^2 - 4x = 10
x^2 - 4x - 10 = 0
Step 2: Take the coefficient of x (which is -4) and divide it by 2, then square the result.
-4 / 2 = -2
(-2)^2 = 4
Step 3: Add the result from step 2 (4) to both sides of the equation.
x^2 - 4x + 4 = 10 + 4
x^2 - 4x + 4 = 14
Step 4: Factor the left side of the equation as a perfect square trinomial.
(x - 2)^2 = 14
Step 5: Take the square root of both sides of the equation.
√((x - 2)^2) = √14
x - 2 = ±√14
Step 6: Solve for x by adding 2 to both sides of the equation.
x = 2 ±√14
So, the solutions to the equation x^2 - 4x = 10 are x = 2 + √14 and x = 2 - √14.