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December 17, 2014

December 17, 2014

Posted by **sdfsgfsf** on Wednesday, June 11, 2008 at 10:01am.

- chemistry -
**DrBob222**, Wednesday, June 11, 2008 at 10:42amheat lost by alloy + heat gained by water = 0

heat lost or gained = mass x specific heat x (Tfinal-Tinitial).

mass alloy x specific heat alloy x (Tfinal-Tinitial) + mass water x specific heat water x (Tfinal-Tinitial) = 0

You must look up the specific heat of water, the specific heat of the alloy is the only unknown, you know the mass of water and mass of the alloy. I note you spelled Celsius two ways, the correct way is Celsius, not Celcius, probably just a typo. Post your work if you get stuck.

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