Thursday

December 18, 2014

December 18, 2014

Posted by **shelly** on Monday, June 9, 2008 at 10:50pm.

- physics -
**drwls**, Tuesday, June 10, 2008 at 12:44am1. For your first question, use the lens equation

1/do + 1/di = 1/f, where f is the focal length and do is the object distance, 8 cm.

2. For your second question, replace f = 6 cm with f = -6 cm, keep do = 8 cm and solve for di. The magnification is the absolute value of di/do

**Answer this Question**

**Related Questions**

physics --- - A concave spherical mirror has a radius of curvature 15 cm. A 1 cm...

physics - A concave spherical mirror has a radius of curvature 15 cm. A 1 cm ...

Physics - An object is placed 30mm in front of a lens. An image of the object is...

Physics - A mirror produces an image that is located 50.0 cm behind the mirror, ...

marymount academy - 1.An object 2.5cm high is placed 10cm from a converging lens...

physics - A 4.5 cm tall object is placed 20 cm in front of a spherical mirror. ...

Physics - (1) A virtual image -7 cm tall and 17 cm away from a mirror is created...

Physics - (1) A virtual image -7 cm tall and 17 cm away from a mirror is created...

physics - A convex spherical mirror has a focal length of -20 cm. An object is ...

Physics - A concave spherical mirror has a radius of curvature 15 cm. A 1 cm ...