Posted by **shelly** on Monday, June 9, 2008 at 10:50pm.

the focal length of this mirror is 6 cm and the object is located 8 cm away from the mirror. calculate the position of the image formed by the mirror. suppose the converging mirror is replaced by a diverging mirror with the same radius of curvature that is the same distance from the object for this mirror how does the size of the image compare with that of the object? is it larger than the object, smaller than the object, or the same size as the object?

- physics -
**drwls**, Tuesday, June 10, 2008 at 12:44am
1. For your first question, use the lens equation

1/do + 1/di = 1/f, where f is the focal length and do is the object distance, 8 cm.

2. For your second question, replace f = 6 cm with f = -6 cm, keep do = 8 cm and solve for di. The magnification is the absolute value of di/do

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