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March 6, 2015

March 6, 2015

Posted by **jerson** on Monday, June 9, 2008 at 9:31pm.

again my teacher said the answer is ellipse with center (-4,4), foci at (-4± V3, 4) but dont get how she got it

- alg -
**Damon**, Monday, June 9, 2008 at 9:46pmYou have not given us the problem that we are supposed to solve. I can not even reverse engineer it from what you have written. What conic section?

- alg -
**jerson**, Monday, June 9, 2008 at 11:05pmsorry the problem is 4x^2 + 7y^2 + 32x-56y +148=0

- alg -
**Damon**, Tuesday, June 10, 2008 at 4:48am4 x^2 + 32 x + 7 y^2 -56 y = -148

x^2 + 8 x + (7/4)y^2 - 14 y = -37

x^2 + 8 x + 16 + (7/4) y^2 -14 y = -21

(x+4)^2 + (7/4) y^2 - 14 y = -21

(4/7)(x+4)^2 + y^2 - 8 y = -12

(4/7)(x+4)^2 + y^2-8y+16 = 4

(4/7)(x+4)^2 + (y-4)^2 = 4

(x+4)^2 /7 + (y-4)^2/4 = 1

ellipse with center at (-4,4)

a^2 = 7

b^2 4

so a = sqrt 7

b = 2

center to focus = sqrt(7-4) = sqrt 3

etc

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