Posted by Katie on Monday, June 9, 2008 at 5:58pm.
solve 2sin^2x+sinx1=0 in the interval [0, 2pi0

trig  drwls, Monday, June 9, 2008 at 6:41pm
Call sin a new variable y and solve the quadratic equation for y:
2y^2 +y 1 = 0
(2y  1) (y + 1) = 0
y = sin x = 1/2 or 1