Posted by **Miley** on Monday, June 9, 2008 at 3:40pm.

Can someone please explain to me how to get the 16 in this equation. I get how to get everything else but i don't know how to get the 16.

A hyperbola with foci: (0,5) (0,-5)and vertices: (0,3) (0,-3). So i got y^2/9-x^2/16=1. but how do you get the 16?

## Answer this Question

## Related Questions

- algebra - Can someone please help... a hyperbola has vertices (+-5,0) and one ...
- math30 - The equation of the hyperbola is (x-3)^2/4 - (y+1)^2/16 =-1. What is ...
- agebra - Can someone please help me.. find an equation that models the path of a...
- algebra - a hyperbola has vertices (+-5,0) and one focus (6,0) what is the ...
- Algebra 2 - a hyperbola is centered at (3,7). The vertices are (9,7) and (-3,7...
- Algebra II-Please check fpr explanation - I have a question concerning this ...
- Algebra - HELP! I am not sure how I would even start this problem or solve it. A...
- Algebra 2 Mannn - 9x^2-y^2-72x+8y+119. how do i change this equation from ...
- algebra - find an equation that models the path of a satelite if its path is a ...
- algebra - how would you solve this; Write an equation for the hyperbola with ...

More Related Questions