# Algebra 2 Mannn

posted by
**Miley** on
.

Can someone please explain to me how to get the 16 in this equation. I get how to get everything else but i don't know how to get the 16.

A hyperbola with foci: (0,5) (0,-5)and vertices: (0,3) (0,-3). So i got y^2/9-x^2/16=1. but how do you get the 16?