Find the function value.
Given that f(x) = 5x2 - 2x, find f(t + 2).
I am stumped on this one... and I typed it in wrong.
f(x)=5x^2-2x, find f(t+2)
Well, if f(x) = 5x^2 - 2x, then to find f(t + 2), we need to substitute t + 2 for x in the function and simplify.
So, let's plug in t + 2 for x:
f(t + 2) = 5(t + 2)^2 - 2(t + 2)
Now, let's have some fun with math! We're going to expand the square and distribute the terms:
f(t + 2) = 5(t^2 + 4t + 4) - 2(t + 2)
Okay, now let's simplify further:
f(t + 2) = 5t^2 + 20t + 20 - 2t - 4
And finally, let's combine like terms:
f(t + 2) = 5t^2 + 18t + 16
Ta-da! We found the function value of f(t + 2).
To find f(t + 2), we need to substitute (t + 2) in place of x in the given function f(x) = 5x^2 - 2x.
Step 1: Substitute (t + 2) in place of x in the function.
f(t + 2) = 5(t + 2)^2 - 2(t + 2)
Step 2: Simplify the expression inside the parentheses.
f(t + 2) = 5(t^2 + 4t + 4) - 2(t + 2)
Step 3: Apply the distributive property to remove the parentheses.
f(t + 2) = 5t^2 + 20t + 20 - 2t - 4
Step 4: Combine like terms.
f(t + 2) = 5t^2 + 18t + 16
Therefore, the value of f(t + 2) is 5t^2 + 18t + 16.
To find the function value f(t + 2), you need to substitute (t + 2) in place of x in the given function f(x) = 5x^2 - 2x. Here's how you can do it:
Step 1: Replace x with (t + 2) in the function.
f(t + 2) = 5(t + 2)^2 - 2(t + 2)
Step 2: Simplify the expression by expanding and combining like terms.
f(t + 2) = 5(t^2 + 4t + 4) - 2(t + 2)
= 5t^2 + 20t + 20 - 2t - 4
= 5t^2 + 18t + 16
Therefore, the function value f(t + 2) is 5t^2 + 18t + 16.
5 (t+2)^2 - 2 (t+2)
5 (t^2 + 4 t + 4) - 2 t - 2
5 t^2 .... etc