what is the maximum number of grams of PH3 that can be formed when 6.2grams of phosphorus reacts with 4.0 grams of hydrogen to form PH3?
P4+6H2--> 4PH3
How many moles is 6.2 grams of P?
How many moles is 4grams of H2?
Notice in the balanced reaction it takes 1.5 moles of H2 for every one mole of P.
If you have more of H than that, then the limiting reactant is P, otherwise the limiting reactant is H2.
Use the moles of the limiting reactant to determine the moles of PH3.
2mol
To determine the maximum number of grams of PH3 that can be formed, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product formed.
1. Convert the given masses of phosphorus and hydrogen to moles using their respective molar masses.
- Molar mass of phosphorus (P) = 30.97 g/mol
- Molar mass of hydrogen (H) = 1.01 g/mol
Moles of phosphorus (P) = 6.2 g / 30.97 g/mol
Moles of hydrogen (H) = 4.0 g / 1.01 g/mol
2. Use the balanced chemical equation to find the stoichiometric ratio between phosphorus and hydrogen in the balanced equation:
- Balanced equation: P4 + 6H2 → 4PH3
From the equation, we can see that 1 mole of phosphorus reacts with 6 moles of hydrogen to produce 4 moles of PH3.
3. Calculate the moles of PH3 that can be formed using the stoichiometry:
- Moles of PH3 = (moles of hydrogen) / 6
4. Determine the limiting reactant:
- Compare the number of moles of PH3 that can be formed from each reactant. The reactant that yields the fewer moles of PH3 is the limiting reactant.
5. Calculate the maximum number of grams of PH3 that can be formed using the moles of PH3 and the molar mass of PH3 (33.97 g/mol).
I hope this helps! Let me know if you have any further questions.