Posted by Sam on Thursday, June 5, 2008 at 10:30pm.
Find the equation of the tangent to y=2xe^x at the point where x=0
So I found the first derivative by doing the sum rule and product rule.
I got e^(x)(x1)
Then I found the slope by substituting 0 for x and got 1.
Then I found y by substituting 0 into the original equation and got 2.
So for my final equation after finding b I had y=1x+2
But in the back of the book the answer says x+y2=0.

Calculus again  Count Iblis, Thursday, June 5, 2008 at 10:54pm
You can simplify things right from the start by writing the equation for the tangent as:
Delta Y/DeltaX = y'
The derivative y' is to be evaluated at the point where you take the tangent, Delta Y and Delta x are the differences in the y and x coordinate relative to the values they take at the point where the tangent touches the graph of the function.
Answer This Question
Related Questions
 Calculus derivative  find the slope m and an equation of the tangent line to ...
 Math, Calculus  Find the derivative of the function. y= xcosx  sinx What's the...
 Calculus  I have a two part question that pertains to a curve (r(x)) and its ...
 calculus  First I would find the first derivative which is the slope and then ...
 got a couple of calculus questions  1. What is the equation of the tangent line...
 Math  Find the equation of the line tangent to curve x=sec(t), y=tan(t), at t=...
 Calculus  Explain the global optimization process for a continuous function ...
 Calculus  Explain the global optimization process for a continuous function ...
 calculus  Consider line segments which are tangent to a point on the right half...
 Calc I  if f(t)=sqrt(4t+1) find f''(2) I got the first derivative to be: 1/2(4t...
More Related Questions