Saturday
October 25, 2014

Homework Help: Calculus again

Posted by Sam on Thursday, June 5, 2008 at 10:30pm.

Find the equation of the tangent to y=2-xe^x at the point where x=0

So I found the first derivative by doing the sum rule and product rule.
I got e^(x)(x-1)

Then I found the slope by substituting 0 for x and got -1.

Then I found y by substituting 0 into the original equation and got 2.

So for my final equation after finding b I had y=-1x+2

But in the back of the book the answer says x+y-2=0.

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