Posted by **Mike** on Thursday, June 5, 2008 at 10:43am.

Cart A (mass 10kg) and cart B (mass= 10kg) are connected by a compressed spring. When the spring is released, cart A has a velocity of 5m/s east. Find:

a. momentum of cart A

b. momentum of cart B

c. velocity of cart B

- Phys. -
**drwls**, Thursday, June 5, 2008 at 11:07am
There should be a figure to go with this question. If there are no other forces acting other than the spring, and the center of mass of the two carts remains fixed, then

a) Momentum of cart A = 10 kg*5 m/s (east) = 50 kg m/s east-50 kg m/s

The minus sign means west.

(c) Cart B momentum divided by 10 kg

## Answer this Question

## Related Questions

- Physics - Cart A (mass 10kg) and cart B (mass= 10kg) are connected by a ...
- PHYSICS - A roller coaster powered by a spring launcher follows a frictionless ...
- physics - A 10.0 kg cart and a 15 kg cart are locked together with a compressed ...
- science - A 10.0 kg cart and a 15 kg cart are locked together with a compressed ...
- Physics - cart A with mass: 512g (0.512kg) is on a horizontal table. the cart is...
- Physics - I think I chose the correct answer. In a closed system, two carts have...
- physics - A 1.o kg cart A and 2.0 kg cart B are at rest on a frictionless table...
- Physics - Cart A has a mass of 10kg and is moving towards cart B at a speed of ...
- physics - A 10kg runaway grocery cart runs into a spring with spring constant ...
- physics please help - suppose a cart of mass m = 969 g is initial moving at ...

More Related Questions