Thursday

July 31, 2014

July 31, 2014

Posted by **Mike** on Thursday, June 5, 2008 at 10:43am.

a. momentum of cart A

b. momentum of cart B

c. velocity of cart B

- Phys. -
**drwls**, Thursday, June 5, 2008 at 11:07amThere should be a figure to go with this question. If there are no other forces acting other than the spring, and the center of mass of the two carts remains fixed, then

a) Momentum of cart A = 10 kg*5 m/s (east) = 50 kg m/s east-50 kg m/s

The minus sign means west.

(c) Cart B momentum divided by 10 kg

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