Posted by Mike on Thursday, June 5, 2008 at 10:43am.
There should be a figure to go with this question. If there are no other forces acting other than the spring, and the center of mass of the two carts remains fixed, then
a) Momentum of cart A = 10 kg*5 m/s (east) = 50 kg m/s east-50 kg m/s
The minus sign means west.
(c) Cart B momentum divided by 10 kg
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