Posted by Anonymous on Wednesday, June 4, 2008 at 10:21pm.
Integral of dx/sqrt(4-x^2
Let x = 2u and that becomes
2 du/sqrt(4 - 4u^2)
Integral of du/(sqrt(1-u^2)
= sin^1 u = sin^-1(x/2)
OK so far.. sin-1(sqrt3/2) - sin^-1 0
= pi/3
I agree with your answer