Posted by **Anonymous** on Wednesday, June 4, 2008 at 9:27pm.

integral 1 to 500 (13^x - 11^x) + integral 2 to 500 (11^x - 13^x) dx =

(answer: 14.946)

I tried typing the integrals in the graphing calculator to get the answer, but it says overflow. Any help on solving this? Thanks!

- Calculus -
**drwls**, Wednesday, June 4, 2008 at 9:53pm
Note that the integrand of #2, is inues that of #1, so that the two integrals cancel over the 2 to 50 range, just the integral of (13^x - 11^x) from 1 to 2.

Recognizing that the 2 to 500 part of the integrals, which are extremely large numbers, cancel out should help you avoid the overflow problem.

The answer is integral 1 to 2

(13^x - 11^x) dx

The integral of a^x is a^x/log a, so

The indefinite integral is

13^x/log 13 - 11^x/log 11

At x = 2, this is 65.888 - 50.461 = 18.427

At x = 1, is it 5.068 - 4.587 = 0.481

Take the difference of those two numbers for the final answer. it is 17.946.., not 14.946

I think you typed it wrong.

- Calculus -
**Anonymous**, Wednesday, June 4, 2008 at 10:31pm
I typed the the answer correctly. At x=2, 65.888-50.461, which is equal to 15.427. So, 15.427-.481= 14.946. Thanks for the help!

- Calculus -
**drwls**, Wednesday, June 4, 2008 at 10:40pm
yes, it was me who typed the 18 wrong. duh. Anyway, I'm glad that helped.

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