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September 16, 2014

September 16, 2014

Posted by **Anonymous** on Wednesday, June 4, 2008 at 6:39pm.

Did I take the first derivative correctly?

I seem to get undefined when I isolate for x to determine the extreme values?

f'(x) = -e/ x + 2e/2x

f'(x) = (-2ex + 2ex) / 2x^2

- Calculus - First Derivative -
**drwls**, Wednesday, June 4, 2008 at 7:03pmWhat does e/x represent? e divided by x or e^x ? In either case, I don't agree with your answer.

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