Original Equation: f(x) = e^(-x) - e^(-2x)
Did I take the first derivative correctly?
I seem to get undefined when I isolate for x to determine the extreme values?
f'(x) = -e/ x + 2e/2x
f'(x) = (-2ex + 2ex) / 2x^2
Calculus - First Derivative - drwls, Wednesday, June 4, 2008 at 7:03pm
What does e/x represent? e divided by x or e^x ? In either case, I don't agree with your answer.