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January 27, 2015

January 27, 2015

Posted by **Anne** on Wednesday, June 4, 2008 at 6:32pm.

a. getting at least one head on the coins and a 6 on the die?

b. getting a head on both coins and a 4 on the die ?

c. getting a head on both coins and a 3 or a 5 on the die?

d. getting a head on both coins with anything on the die?

- statistics -
**ben**, Wednesday, June 4, 2008 at 6:47pmA. 1/12

b. 1/24

c. 1/12

d. 1/4

I THINK these answers are correct, if this is for a major grade, ask somebody and compare my answers to theirs.

- statistics -
**Anne**, Wednesday, June 4, 2008 at 6:49pmAnother person had the exact same answers as you. This is for a major grade! Thank You!!

- statistics -
**Anne**, Wednesday, June 4, 2008 at 7:23pm. P(at least one head) is the same as 1 - P(no heads). Now, P(no heads) = 1/2 * 1/2 = 1/4 so P(at least one head) = 3/4. P(6) = 1/6. The total is 3/4 * 1/6 = 1/8.

actually for part a is it possible the answer could be 1/8?

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**drwls**, Thursday, June 5, 2008 at 12:46amYes, the answer to (a) is 3/4 x 1/6 = 1/8

3/4 is the probability of getting at least one head in two coin tosses.

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