Algebra
posted by Danny .
can someone help me with this word problem?
if a pro basketball player has a vertical leap of about 20 inches, what is his hangtime?

It is twice the time that it would take an object to fall 20 inches.
hangtime T = 2 * sqrt(2H/g)
H = 20"/(12 in/ft) = 1.6667 ft
g = 32.2 ft/s^2
T = 0.64 s