use boyles law to solve for the missing value in the following
P1=0.75atm,V2=435ml,P2=0.48atm, V1=?
278.4
P1V1 = P2V2.
Plug in the numbers and solve for V1.
To solve for the missing value (V1) using Boyle's Law, we can use the equation:
P1 * V1 = P2 * V2
Where:
P1 is the initial pressure (0.75 atm)
V2 is the final volume (435 mL)
P2 is the final pressure (0.48 atm)
V1 is the initial volume (unknown)
Rearranging the equation to solve for V1:
V1 = (P2 * V2) / P1
Substituting the given values:
V1 = (0.48 atm * 435 mL) / 0.75 atm
Performing the calculation:
V1 = (0.48 * 435) / 0.75 mL
V1 = 261.6 mL / 0.75 mL
V1 ≈ 348.8 mL
Therefore, the missing value (V1) is approximately 348.8 mL.
Boyle's Law states that the pressure and volume of a gas are inversely proportional, assuming the temperature and the amount of gas remain constant. The formula for Boyle's Law is:
P1 * V1 = P2 * V2
Given:
P1 = 0.75 atm
V2 = 435 mL
P2 = 0.48 atm
V1 = ?
To solve for the unknown value, V1, we can rearrange the formula:
V1 = (P2 * V2) / P1
Plugging in the known values:
V1 = (0.48 atm * 435 mL) / 0.75 atm
Now we can calculate the missing value:
V1 = 278.4 mL
Therefore, V1 is equal to 278.4 mL.