Posted by electra on Tuesday, June 3, 2008 at 11:11pm.
I think that is 1/2 the b term (1/2*22 and that squared) so the term to be added would be 11^2 = 121.
x^2 + 22x + 121 = (x+11)(x+11)
(x + a)(x + a)
=x^2 + 2ax + a^2
In the problem,
2ax=22x
2a=22
a=11
substituting back
(x + 11)(x + 11)
x^2 + 22x + 121
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