6(x^2 -2) = 12
I have a huge test tmr. stuck on this have no idea why? Can anyone help me figure this quadratic equation? PLEASE !
Assistance needed.
6(x^2 -2) = 12
I would write this as
6x^2 -12 = 12, then
6x^2 -24 = 0
6(x^2-4) = 0
6(x+2)(x-2) = 0
x = +2
x = -2
To solve this equation, we need to isolate the variable x on one side of the equation.
Step 1: Distribute the 6 to the terms inside the parentheses:
6x^2 - 12 = 12
Step 2: Move the constant term (in this case, -12) to the other side of the equation by adding 12 to both sides:
6x^2 = 12 + 12
6x^2 = 24
Step 3: Divide both sides of the equation by 6 to solve for x:
6x^2/6 = 24/6
x^2 = 4
Step 4: Take the square root of both sides of the equation to solve for x:
√(x^2) = √4
x = ±2
Therefore, the solution to the equation 6(x^2 - 2) = 12 is x = ±2.