Posted by sam on Tuesday, June 3, 2008 at 9:53pm.
You might want to use a table of integrals for the first term. Most people prefer to call the "antiderivative" the (indefinite) integral.
In your case the integral is
F(t) = 2 tan t -2t^3 + C
where C is an arbitary constant.
Since F(0) = 0, C = 0
Now solve for F(5)
when i plug this answer in I get -500 is this correct?
I get 2 tan 5 - 2*125 = -249.8
The "5" is understood to be in radians. The -2t^3 term dominates
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