N2 (g) + 3 CL2 (g) ---> 2 NCL3 (g)
delta H = + 230 kj
a) What mass of N2 would absorb 96.5 kj of heat as it reacts?
b) What volume of Cl2 at STP would be required to react with the N2 in part (a)?
Chemistry - bobpursley, Tuesday, June 3, 2008 at 9:39pm
I will be happy to critique your thinking.
Chemistry - Soba, Tuesday, June 3, 2008 at 9:42pm
I don't know how to find mass with the enthalpy formula.
Chemistry - DrBob222, Tuesday, June 3, 2008 at 9:54pm
Just rephrase the question.
If 230 kJ is delta H for 1 mol of N2, then how many mols would account for96.5 kJ
Chemistry - Soba, Tuesday, June 3, 2008 at 10:28pm