Posted by **sabrina** on Tuesday, June 3, 2008 at 1:12pm.

a rectangle is 4 times as long as it is wide. a second triangle is 5 centimeters longer and 2 centimeters wider than the first. the area of the second rectangle is 270 square centimeters greather than the first. what are the dimensions of the original rectangle? how would i solve this question?

- algebra -
**Reiny**, Tuesday, June 3, 2008 at 1:20pm
first triangle : x by 4x

second triangle : 4x+5 by x+2

area of first = x(4x)

area of second = (4x+5)(x+2)

so (4x+5)(x+2) - x(4x) = 270

solve for x, you should get x=20

(check: original is 20 by 80, Area = 1600

second is 22 by 85, Area = 1870)

difference in area = 1870-1600 = 270

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