So if there is Ag2CrO4, the metal wire, in a SCE and Hg2Cl2 which will be the anode and cathode?
To determine which substance will act as the anode and cathode, we need to consider their redox potentials. The substance with the higher reduction potential will be reduced at the cathode and the substance with the lower reduction potential will be oxidized at the anode.
To find the reduction potential for Ag2CrO4, we can look up its standard reduction potential in a table of standard reduction potentials. Let's assume we find that the reduction potential for Ag2CrO4 is +0.50 V.
For Hg2Cl2, we can similarly find its reduction potential value, which let's say is +0.30 V.
Now, compare the reduction potentials of Ag2CrO4 and Hg2Cl2. Since the reduction potential of Ag2CrO4 (+0.50 V) is higher than that of Hg2Cl2 (+0.30 V), Ag2CrO4 will be reduced at the cathode, while Hg2Cl2 will be oxidized at the anode.
Therefore, in this scenario, Ag2CrO4 will be the cathode, and Hg2Cl2 will be the anode.