Posted by chemistrybuddy on Monday, June 2, 2008 at 11:34pm.
Naoh + CH3COOH = CH3COONa + H2O
So i am going titrate acid(CH3COOH) to base (Naoh). How do i measure solubility of Acetic Acid( CH3COONa ) from that? check when it forms a precipitate?
The equation is
NaOH + CH3COOH ==> CH3COONa + H2O
Now, what is your question?
soorry i was writing the equation but computer went weird on me. So i titrate acid ( ch3cooh) to base ( naoh) and get sodium acetate ch3coohna but how do i measure solubility of sodium acetate? do i wait just until a precipitate forms at equilibrium(saturation)?
You need to let us know more about the procedure. Titration alone will not tell you the solubility. If you are using an indicator to show the end point of the titration, then molarity of NaOH*volume NaOH will be the mols CH3COONa formed and you can find the grams CH3COONa from that. But whether that dissolves or not depends upon the amount of water in the titration vessel.
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