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Posted by on Monday, June 2, 2008 at 11:34pm.

hi, i am trying to develop a lab where i find the solubility of Sodium acetate. I was wondering in i was in the right path.

We are given these three compounds:
Acetic acid aka vinegar
baking soda (sodium hydrogen carbonate)
0.100mol/l Naoh(aq)
0.100/l HCL(aq)

So we are not given Sodium acetate so we have to first titrate NAOH with Acetic Acid which produces the sodium acetate and water. here is the equation.

  • chemistry - , Monday, June 2, 2008 at 11:34pm

    Naoh + CH3COOH = CH3COONa + H2O

    So i am going titrate acid(CH3COOH) to base (Naoh). How do i measure solubility of Acetic Acid( CH3COONa ) from that? check when it forms a precipitate?

  • chemistry - , Tuesday, June 3, 2008 at 12:00am

    The equation is
    NaOH + CH3COOH ==> CH3COONa + H2O

    Now, what is your question?

  • chemistry - , Tuesday, June 3, 2008 at 12:55am

    soorry i was writing the equation but computer went weird on me. So i titrate acid ( ch3cooh) to base ( naoh) and get sodium acetate ch3coohna but how do i measure solubility of sodium acetate? do i wait just until a precipitate forms at equilibrium(saturation)?

  • chemistry - , Tuesday, June 3, 2008 at 10:54am

    You need to let us know more about the procedure. Titration alone will not tell you the solubility. If you are using an indicator to show the end point of the titration, then molarity of NaOH*volume NaOH will be the mols CH3COONa formed and you can find the grams CH3COONa from that. But whether that dissolves or not depends upon the amount of water in the titration vessel.

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