Thursday
March 23, 2017

Post a New Question

Posted by on Monday, June 2, 2008 at 11:31pm.

hi, i am trying to develop a lab where i find the solubility of Sodium acetate. I was wondering in i was in the right path.

We are given these three compounds:
Acetic acid aka vinegar
baking soda (sodium hydrogen carbonate)
0.100mol/l Naoh(aq)
0.100/l HCL(aq)

So we are not given Sodium acetate so we have to first titrate NAOH with Acetic Acid which produces the sodium acetate and water. here is the equation.

Naoh + CH3COOH = CH3COONa + H2O

So i am going titrate acid(CH3COOH) to base (Naoh). How do i measure solubility of Acetic Acid( CH3COONa ) from that? check when it forms a precipitate?

  • chemistry - , Monday, June 2, 2008 at 11:32pm

    hi, i am trying to develop a lab where i find the solubility of Sodium acetate. I was wondering in i was in the right path.

    We are given these three compounds:
    Acetic acid aka vinegar
    baking soda (sodium hydrogen carbonate)
    0.100mol/l Naoh(aq)
    0.100/l HCL(aq)

    So we are not given Sodium acetate so we have to first titrate NAOH with Acetic Acid which produces the sodium acetate and water.So i am going titrate acid(CH3COOH) to base (Naoh). here is the equation.

    Naoh + CH3COOH = CH3COONa + H2O

  • chemistry - , Monday, June 2, 2008 at 11:32pm

    hi, i am trying to develop a lab where i find the solubility of Sodium acetate. I was wondering in i was in the right path.

    We are given these three compounds:
    Acetic acid aka vinegar
    baking soda (sodium hydrogen carbonate)
    0.100mol/l Naoh(aq)
    0.100/l HCL(aq)

    So we are not given Sodium acetate so we have to first titrate NAOH with Acetic Acid which produces the sodium acetate and water.So i am going titrate acid(CH3COOH) to base (Naoh). here is the equation.
    Naoh + CH3COOH = CH3COONa + H2O

  • chemistry - , Monday, June 2, 2008 at 11:58pm

    Three incomplete posts. All the same. What is your question?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question