Posted by Kim on Monday, June 2, 2008 at 10:25pm.
It is very important to use brackets.
I will assume you meant
1/9 -(K+3)/(72k) = 1/(9k) - (k-1)/(8k)
multiply each term by 72k to get
72k - (k-3) = 8 - (k-1)
I am sure you can take it from there.
Related Questions
math - 1/9 - (k+3)/(72K) = 1/(9k) - (k-1)/(8k)
physics multiplying vectors - In the product F = qv · B , take q = 4, = 2...
precalc - simplify: (x^-2 - y^-2) / (x^-1 - y^-1) i know you have to get rid of ...
physics please help me - I am solving a problem and someone tol me to use this ...
PHYSICS - please help!!! - In the product F = qv · B , take q = 4, v = 2....
physics multiplying vectors - n the product F = qv · B , take q = 4, = 2....
Algebra - Hi! Today I was absent from my algebra class, and they learned how to ...
Math - I am a parent of a 10 year old, 5th grader and my hubby and I just can...
algebra 2 - i cant figure out how to solve this? T with two over powe +7T-18+0 ...
algebra - how would i figure out a problem like: a^2 + b^2 = 5^2 is there a ...
For Further Reading