Saturday

April 19, 2014

April 19, 2014

Posted by **sarah** on Saturday, May 31, 2008 at 7:06pm.

- COLLEGE PHYSICS -
**drwls**, Saturday, May 31, 2008 at 7:26pmThe initial total(kinetic + potential) energy, with respect to ground level zero P.E., is

(1/2) M V^2 + M g H = 1728 J + 147,150 J = 148,778 J. If it loses 20,000 J before reaching the next peak, and has 2.0 m/s velocity there, then

128,778 = (1/2) M V^2 + M g H'

= 1200 + M g H'

Solve for the new maximum height, H'. I get H' = 21.7 m.

I used 9.81 m/s^2 for g. No guarantees here.. check my assumptions and calculations.

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