I don't get 2 math problems, if I could see how it's completed then I can do the other problems on my own. Can someone pls help me this is so hard. =(

Factor completely.

1. 0.49y^2-0.0025=

2. 6q^2+19qp+10p^2=

Omg this is a longggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg gggggggggg Ago.

Sure, I can help you with these math problems step by step. Let's start with the first one.

1. Factor completely: 0.49y^2 - 0.0025

To factor this expression, we need to look for common factors among the terms. In this case, there are no common factors among the terms.

Next, we can rewrite the expression by factoring out the greatest common factor (GCF), which in this case is 0.0025:

0.49y^2 - 0.0025 = 0.0025 * (0.49y^2/0.0025 - 1)

Now, simplify the expression inside the parentheses:

0.49y^2/0.0025 - 1 = 196y^2 - 1

So the completely factored form of 0.49y^2 - 0.0025 is:

0.49y^2 - 0.0025 = 0.0025 * (196y^2 - 1)

Now, let's move on to the second problem.

2. Factor completely: 6q^2 + 19qp + 10p^2

Again, let's look for common factors among the terms. In this case, there are no common factors among the terms.

Next, let's try factoring by splitting the middle term. This means we need to find two numbers that multiply to give the product of the coefficient of the squared term (6) and the constant term (10), which is 60, and also add up to the coefficient of the linear term (19). The numbers that satisfy these conditions are 15 and 4.

Now, rewrite the middle term (19qp) as the sum of 15qp and 4qp:

6q^2 + 15qp + 4qp + 10p^2

Now, we can group the terms and factor by grouping:

(6q^2 + 15qp) + (4qp + 10p^2)

Take out the greatest common factor from the terms in each group:

3q(2q + 5p) + 2p(2q + 5p)

Notice that we have a common factor, (2q + 5p), in both groups. We can factor it out:

(2q + 5p)(3q + 2p)

So the completely factored form of 6q^2 + 19qp + 10p^2 is:

6q^2 + 19qp + 10p^2 = (2q + 5p)(3q + 2p)

Now that you've seen the step-by-step process of factoring these expressions, you should be able to solve similar problems on your own. Good luck with the rest of your math problems! If you have any more questions, feel free to ask.