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September 22, 2014

September 22, 2014

Posted by **queros** on Thursday, May 29, 2008 at 5:58am.

- mathematics -
**drwls**, Thursday, May 29, 2008 at 10:23amUse separation of variables. I don't know if the y^(1/2) is supposed to be in the denominator or not. Let's supposed it is not. Then

dy/dx= -[(ln(x))/(x^2)]*y^1/2

y(-1/2) dy = -ln(x)/x^2 dx

Integrate both sides separately, and add a constant.

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