Thursday

July 31, 2014

July 31, 2014

Posted by **Andrea** on Wednesday, May 28, 2008 at 8:49pm.

a)9 b)6 c)4 d)3 e)2

So as a result section A has zero for the variance. I am having trouble figuring out the correct equation to solve this problem.

- Stats -
**PsyDAG**, Thursday, May 29, 2008 at 11:01amVariance = Σx^2/N, where x = X-μ. Since Σx^2 = 0 for the first group, it will contribute nothing to the Σx^2, so that term will remain the same for the combined class, but the N will increase from 15 to 20.

For the second group, since Variance = Σx^2/N,

Σx^2 = Variance * N = 12 * 15 = 180

Thus for the second group, variance = 180/20 = 9

However, the standard deviation is the square root of the variance. You should be able to calculate that.

I hope this helps. Thanks for asking.

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